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Question

Electrons traveling at a velocity of 2.4×106ms1 enter a region of cross electric and magnetic fields as shown in fig. If the electric field is 3.0×106Vm and the flux density of the magnetic field is 1.5 T, the electron upon entering the region of the crossed fields will

162959_aaa31e3a0f5745a5b1f21ff2f545a1b8.png

A
continue to travel undeflected in their original direction
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B
be deflected upward in the plane of the diagram
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C
be deflected downward on the plane of the diagram
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D
none of the above
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Solution

The correct option is C be deflected downward on the plane of the diagram
Electric force acting on particle is qE
=eE upwards
=4.8×1013N
Magnetic force acting on particle=q(v×B)
=evB downwards
=5.76×1013N
FB>FE
Hence particle moves downwards in the plane of diagram.

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