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Question

Electrons used in an electron microscope are accelerated by a voltage of 25 kV. If the voltage is increased by 100 kV then the de-Broglie wavelength associated with electrons would

A
increase by 2 times
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B
decrease by 2 times
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C
increase by 4 times
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D
decrease by 4 times
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Solution

The correct option is B decrease by 2 times
de_broglie wavelength λ=hP
where momentum of the particle P=2mK=2meV
λ=h2meV
We get λ1V
Given : Vi=25kV and V2=100kV
So, voltage is increased by a factor of 4.
Thus wavelength gets reduced by a factor of 2.

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