Electrons used in an electron microscope are accelerated by a voltage of 25kV. If the voltage is increased by 100kV then the de-Broglie wavelength associated with electrons would
A
increase by 2 times
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B
decrease by 2 times
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C
increase by 4 times
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D
decrease by 4 times
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Solution
The correct option is B decrease by 2 times de_broglie wavelength λ=hP where momentum of the particle P=√2mK=√2meV ⟹λ=h√2meV We get λ∝1√V Given : Vi=25kV and V2=100kV So, voltage is increased by a factor of 4. Thus wavelength gets reduced by a factor of 2.