Question

Element $B$ forms ccp structure and $A$ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The formula of bimetallic oxide is:

• A. $A_2{B}_{2}O$
• B. $A_{2}B{O}_4$
• C. $A{B}_2{O}_4$
• D. $A_4{B}_{2}O$

Answer 1

The correct option is C $A{B}_2{O}_4$

$B$ forms ccp structure, number of atom of $B=4$
Total octahedral voids = 4
As per question, $A=50\%$ of octahedral voids $=2$
Total tetrahedral voids = 8
As per question, $O$ occupy tetrahedral voids $=8$
Formula of bimetallic oxide is $A_2{B}_4{O}_8$ or $A{B}_2{O}_4$.