Element $B$ forms ccp structure and $A$ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The formula of bimetallic oxide is:
(JEE Main 2019)

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Solution

$B$ forms ccp structure, number of atom of $B = 4$ . Total octahedral voids = 4. As per question, $A = 50 %$ of octahedral voids $= 2$ . Total tetrahedral voids = 8. As per question, $O$ occupies all tetrahedral voids $= 8$ . Formula of bimetallic oxide is $A_{2} B_{4} O_{8}$ or $A B_{2} O_{4}$ .

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Element B forms ccp structure and A occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The formula of bimetallic oxide is: (JEE Main 2019)

B forms ccp structure, number of atom of B=4. Total octahedral voids = 4. As per question, A=50 % of octahedral voids =2. Total tetrahedral voids = 8. As per question, O occupies all tetrahedral voids =8. Formula of bimetallic oxide is A2B4O8 or AB2O4.

Element $B$ forms ccp structure and $A$ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The formula of bimetallic oxide is:
(JEE Main 2019)

$B$ forms ccp structure, number of atom of $B = 4$ . Total octahedral voids = 4. As per question, $A = 50 %$ of octahedral voids $= 2$ . Total tetrahedral voids = 8. As per question, $O$ occupies all tetrahedral voids $= 8$ . Formula of bimetallic oxide is $A_{2} B_{4} O_{8}$ or $A B_{2} O_{4}$ .