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Element Fe ha...

Question

Element $F e$ has two oxidation states $F e^{2 +}$ & $F e^{3 +}$ , the correct order of radii of these ions will be:

F e^{2 +} < F e^{3 +}

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F e^{2 +} = F e^{3 +}

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F e^{2 +} > F e^{3 +}

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F e^{3 +} \leq F e^{2 +}

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Solution

The correct option is C $F e^{2 +} > F e^{3 +}$
The cation with the greater positive charge will have a smaller radius because of the greater attraction of the electrons to the nucleus.
Therefore, the correct order is: $F e^{2 +} > F e^{3 +}$

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