Question

Element X has electronic configuration 2, 8, 18, 8, 1. Without identifying X,

(a) predict the sign and charge on a simple ion of X.

(b) write if X will be an oxidising agent or a reducing agent. Why ?

Answer 1

a) The X has +1 charge.

(Note: The elements will be Rubidium because it has 37 atomic number. It charge will be +1)

b ) X will lose (oxidised) to form cation, it acts a reducing agent.

Note: $Rb⟶R{b}^{+}+1e^{-}$