Element $^{'} X^{'}$ is having atomic number $28,$ it gives two electrons to element $^{'} Y^{'} .$
Write down the electronic configuration of $^{'} X^{'}$ and its ion

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Solution

$X_{28} - 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{8} 4 s^{2}$

$X \to X^{2 +} + 2 e^{-}$

$X^{2 +} - 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{8}$

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