Question

Elements A, B, C, D and E have the following electronic configurations.
A : $1s^{2}2s^{2}2p^1$
B : $1s^{2}2s^{2}2p^{6}3s^{2}3p^1$
C : $1s^{2}2s^{2}2p^{6}3s^{2}3p^3$
D : $1s^{2}2s^{2}2p^{6}3s^{2}3p^5$
E : $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^2$
Which among these will belong to the same group in the periodic table.

• A. B and C
• B. C and E
• C. D and E
• D. A and B

Answer 1

The correct option is D A and B

Out of these, A and B belong to the same group of the periodic table because they have the same outer electronic configuration, $n{s}^{2}n{p}^1$.