You visited us 1 times! Enjoying our articles? Unlock Full Access!

Boiling

Elements in a...

Question

Elements in a group bond in similar ways, and have very similar interparticle forces.
Of the following halogens bonded to carbon, which molecular compound would be expected to be a gas at room pressure and temperature?

C I_{4}

(carbon tetraiodide)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C B r_{4}

(carbon tetrabromide)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C C l_{4}

(carbon tetrachloride)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C F_{4}

(carbon tetrafluoride)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $C F_{4}$ (carbon tetrafluoride)
Due to the strong chemical stability of $C - F$ bond, it is non-toxic and due to the small size of $F$ it forms a gas. $C F_{4}$ has high stability forming non-flammable gas.

Suggest Corrections

Similar questions

(C F_{4})

(C C l_{4})

C F_{4}

145 K

C C l_{4}

350 K

C I_{4}

C F_{4}

The halides in which the halogen atom is bonded to an sp² hybridised carbon of a carbon-carbon double bond are:

C = 2.5

F = 4.0

I

I I

C - F

Join BYJU'S Learning Program