Question

Elements P and Q react to form a compound $P_x{Q}_y$. R and P react to form $R_y{P}_z$. If x = 2y, z = 3y and P is hydrogen. Identify the pair of compounds.

• A. $H_{2}S{O}_4,H_{3}P{O}_4$
• B. $HCl,HN{O}_3$
• C. $H_{2}S,N{H}_3$
• D. $HF,Na{N}_3$

Answer 1

The correct option is C $H_{2}S,N{H}_3$

Since it is given that P is hydrogen, the acid is binary. Hence the molecular formula of the compound reduces to $H_x{Q}_y$ and $R_y{P}_z$.

Also, $x=2y$ is satisfied only by $H_{2}S$ and the condition $z=3y$ is satisfied by $N{H}_3$.

The compounds are $H_{2}SandN{H}_3$.

Hence, option C is correct.