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Question
Elimination reaction of 2−Bromo-pentane to form pent-1-ene by using potassium tert. butoxide is:
(a) β− Elimination reaction
(b) Follows Hofmann's elimination rule
(c) Dehydrohalogenation reaction
Elimination reaction of 2−Bromo-pentane to form pent-1-ene by using potassium tert. butoxide is:
(a) β− Elimination reaction
(b) Follows Hofmann's elimination rule
(c) Dehydrohalogenation reaction
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Solution
The correct option is D (a), (b), (c)
- Dehydrohalogenation of alkyl halides in presence of bulky base potassium tertiary butoxide is a β-elimination reactions in which major product is obtained by Hofmann’s elimination rule.
- Hofmann elimination rule: “elimination of β−H atom takes place from that β-carbon atom which has more number of H-atoms”.
CH3−CH2−CH2−αC|BrH−βCH32-Bromopentane(CH3)3C−O⊖K⊕−−−−−−−−−−−→CH3−CH2−CH2−CH=CH2Pent-1-ene
- Dehydrohalogenation of alkyl halides in presence of bulky base potassium tertiary butoxide is a β-elimination reactions in which major product is obtained by Hofmann’s elimination rule.
- Hofmann elimination rule: “elimination of β−H atom takes place from that β-carbon atom which has more number of H-atoms”.
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