Eliza deposited Rs. $20, 000$ in a bank at the rate of $10 %$ per annum. Draw a linear graph showing the time and simple interest relationship. Also, find the simple interest for $4$ years.

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Solution

$M o n e y d e p o s i t e d (P) = R s .20000$
$R a t e (R) = 10 %$
$T i m e (T) = 4$
$S . I = \frac{P \times R \times T}{100}$
$= \frac{20000 \times 4 \times 10}{100}$
$= 8000$
$H e n c e, S . I = R s .8000$
$I f T = 1, S . I = R s \frac{20000 \times 1 \times 10}{100}$
$∴ P_{1} = (1, 2000)$
$I f T = 2, S . I = R s 4000$
$∴ P_{2} = (2, 4000)$
$S i m i l a r l y, P_{3} = (3, 6000)$
$H e n c e, g r a p h i s p l o t e d w i t h t h e g i v e n p o i n t s f o u n d .$

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Eliza deposited Rs. 20,000 in a bank at the rate of 10% per annum. Draw a linear graph showing the time and simple interest relationship. Also, find the simple interest for 4 years.

Money deposited (P)=Rs.20000Rate(R)=10%Time(T)=4S.I=P×R×T100=20000×4×10100=8000Hence,S.I=Rs.8000If T=1,S.I=Rs20000×1×10100∴P1=(1,2000)IfT=2,S.I=Rs4000∴P2=(2,4000)Similarly,P3=(3,6000)Hence,graph is ploted with the given points found.

Eliza deposited Rs. $20, 000$ in a bank at the rate of $10 %$ per annum. Draw a linear graph showing the time and simple interest relationship. Also, find the simple interest for $4$ years.