Question

Solve each of the following equations and verify the answer in each case:
16(3x − 5) − 10(4x − 8) = 40

Answer 1

16(3x − 5) − 10(4x − 8) = 40
or, $16\times 3x-16\times 5-10\times 4x-10\times (-8)=40$ [On expanding the brackets]
or, 48x $-$ 80 $-$ 40x + 80 = 40
or, 8x = 40
or, $\frac{8x}{8}=\frac{40}{8}$ [Dividing both the sides by 8]
or, x = 5
Verification:
Substituting x = 5 in the L.H.S.:

$$\begin{gathered} 16(3\times 5-5)-10(4\times 5-8) \\ \Rightarrow 16(15-5)-10(20-8) \\ \Rightarrow 16\left(10\right)-10\left(12\right) \\ \Rightarrow 160-120=40=R.H.S. \end{gathered}$$

L.H.S. = R.H.S.
Hence, verified.