Question

Tick (✓) the correct answer:
Sum of three consecutive integers is 51. The middle one is
(a) 14
(b) 15
(c) 16
(d) 17

Answer 1

(d) 17

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{three}\mathrm{consecutive}\mathrm{integers}\mathrm{be}\mathrm{x},\mathrm{x}+1\mathrm{and}\mathrm{x}+2. \\ \mathrm{Equation}=x+x+1+x+2=51 \\ \Rightarrow 3x+3=51 \\ \Rightarrow 3x=51-3 \\ \Rightarrow 3x=48 \\ \Rightarrow x=\frac{48}{3}=16 \\ \mathrm{Middle}\mathrm{integer}=x+1=16+1=17 \end{gathered}$$