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Which of the following is a pythagorean triplet?
(a) (2, 3, 5)
(b) (5, 7, 9)
(c) (6, 9, 11)
(d) (8, 15, 17)

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Solution

(d) (8,15,17)

This can be understood from the property of Pythagorean triplets. According to this property, for a natural number m, $(2 m, m^{2} - 1, m^{2} + 1)$ is a Pythagorean triplet.
Here, m = 4
2m = 8
m² - 1=15
and m² + 1 = 17

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Similar questions

Q. Which of the following numbers form pythagorean triplet?
i)

2, 3, 4

ii)

6, 8, 10

iii)

9, 10, 11

iv)

8, 15, 17

Q. Tick (✓) the correct answer
Which of the following is a pythagorean triplet?
(a) (2, 3, 5)
(b) (5, 7, 9)
(c) (6, 9, 11)
(d) (8, 15, 17)

Q. Tick (✓) the correct answer

\sqrt[3]{512} = ?

(a) 6
(b) 7
(c) 8
(d) 9

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

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Tick (✓) the correct answer Which of the following is a pythagorean triplet? (a) (2, 3, 5) (b) (5, 7, 9) (c) (6, 9, 11) (d) (8, 15, 17)

(d) (8,15,17)This can be understood from the property of Pythagorean triplets. According to this property, for a natural number m, (2m, m2-1, m2+1) is a Pythagorean triplet.Here, m = 4 2m = 8 m2 - 1=15and m2 + 1 = 17

Tick (✓) the correct answer
Which of the following is a pythagorean triplet?
(a) (2, 3, 5)
(b) (5, 7, 9)
(c) (6, 9, 11)
(d) (8, 15, 17)

(d) (8,15,17)

This can be understood from the property of Pythagorean triplets. According to this property, for a natural number m, $(2 m, m^{2} - 1, m^{2} + 1)$ is a Pythagorean triplet.
Here, m = 4
2m = 8
m² - 1=15
and m² + 1 = 17