Emf of a voltaic cell can be given by:

SRP of anode - SRP of cathode

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SRP of cathode + SOP of anode

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SOP of cathode - SOP of anode

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SOP of cathode + SOP of anode

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Solution

The correct option is B SRP of cathode + SOP of anode
Emf of a voltaic cell can be given by SRP of cathode + SOP of anode.
It is also given by SRP of cathode - SRP of anode
Note: SRP $=$ Standard Reduction potential
SOP $=$ Standard Oxidation Potential.

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(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (i v)) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

(E_{c e l l}^{\circ}) =

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