CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

EMF of cell (Ecell)=

A
(Erd)cathode+(Ered)anode
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(Ered)cathode(Ered)anode
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(Ered)anode(Ered)cathode
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(Eoxd)anode(Eoxd)cathode
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
B (Ered)cathode(Ered)anode
D (Eoxd)anode(Eoxd)cathode
EMF of cell is defined as difference between reduction potential of cathode and anode.
EMF=(Ered)cathode(Ered)anode....(1)
(Ered)anode=(Ered)anode....(2)
(Ered)cathode=(Eoxd)anode....(3)
Substituting (2) & (3) in (1)
EMF=(Ered)anode(Eoxd)cathode

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrochemical series_tackle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon