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Question

EMF of cell (Ecell)=

A
(Erd)cathode+(Ered)anode
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B
(Ered)cathode(Ered)anode
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C
(Ered)anode(Ered)cathode
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D
(Eoxd)anode(Eoxd)cathode
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Solution

The correct options are
B (Ered)cathode(Ered)anode
D (Eoxd)anode(Eoxd)cathode
EMF of cell is defined as difference between reduction potential of cathode and anode.
EMF=(Ered)cathode(Ered)anode....(1)
(Ered)anode=(Ered)anode....(2)
(Ered)cathode=(Eoxd)anode....(3)
Substituting (2) & (3) in (1)
EMF=(Ered)anode(Eoxd)cathode

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