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Integration by Partial Fractions

Emf of the ce...

Question

Emf of the cell $N i / {N i}^{+ 2} (0 / 1 M) | | {A u}^{+ 3} (1.0 M) / A u$ at $298 K$ will be:
${[E}_{N i / N i^{+ 2}}^{o} = 0.25 V, E_{A u / A u^{+ 3}}^{o} = - 1.5 V]$

A

1.75 V

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B

- 1. 7795 V

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C

+ 1. 779 V

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D

+ 0. 7795 V

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Solution

The correct option is B $1.75 V$
$N i / N^{2 +} | | A u^{3 +} / A u$
$E^{o} N i / N i^{2 +} = 0.25 V$
$E^{o} A u / A u^{3 +} = - 1.5 V$
$E^{o} A u^{3 +} / A u = 1.5 V$
$E_{c e l l}^{o} = E^{o} N i / N i^{2 +} + E^{o} A u^{3 +} / A u$
$= 0.25 + 1.5 = 1.75 V$

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