Question

Empirical formula of an ingredient in buffering tablets that has the per cent composition $C:14.25\%,O:56.93\%,Mg:28.83\%$ by mass is $C{O}_{3}Mg$.
If true enter 1, else enter 0.

Answer 1

According to given conditions,
% % $\frac{wt.}{mol.wt.}$ simple ratio empirical formula
$C$ $14.25$ $\frac{14.25}{12}$ $1$
$O$ $56.93$ $\frac{56.93}{16}$ $3$
$Mg$ $28.83$ $\frac{28.83}{24}$ $1$ $C{O}_{3}Mg$
Hence, the given data is correct.