Empty space in HCP lattice is

26 %

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45 %

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90 %

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30 %

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Solution

The correct option is A $26 %$
$P . F = \frac{V o l . o f t h e a t o m s i n o n e u n i t c e l l}{V o l . o f o n e u n i t c e l l} = \frac{6 \times \frac{4}{3} π r^{3}}{24 \sqrt{2} r^{3}} = \frac{π}{3 \sqrt{2}} = 0.74 o r = 74 % ∴ E m p t y s p a c e = 26 %$

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