Question

Encircle the odd one of the following.

• A. $(-9)\times 5\times 6\times (-3)$
• B. $9\times (-5)\times 6\times (-3)$
• C. $(-9)\times (-5)\times (-6)\times 3$
• D. $9\times (-5)\times (-6)\times 3$

Answer 1

The correct option is C

$(-9)\times (-5)\times (-6)\times 3$

Solve (A), (B), (C), and (D).

$$\begin{gathered} \left(A\right)\Rightarrow (–9)\times 5\times 6\times (–3) \\ \Rightarrow 810 \\ \left(B\right)\Rightarrow 9\times (–5)\times 6\times (–3) \\ \Rightarrow 810 \\ \left(C\right)\Rightarrow (–9)\times (–5)\times (–6)\times 3 \\ \Rightarrow -810 \\ \left(D\right)\Rightarrow 9\times (–5)\times (–6)\times 3 \\ \Rightarrow 810 \end{gathered}$$

Here, $\left(A\right)=\left(B\right)=\left(D\right)$

Hence, $\left(C\right)$ is the odd one.