Encircle the odd one of the following- a -9 - 5 - 6 - -3 b 9 - -5 - 6 - -3 c -9 - -5 - -6 - 3 d 9 - -5 - -6 - 3

(a) ( 9) × 5 × 6 × ( 3) = ( 45) × ( 18) = 810 (b) 9 × ( 5) × 6 × ( 3) = ( 45) × ( 18) = 810 (c) ( 9) × ( 5) × ( 6) × 3 = 45 × ( 18) = 810 (d) 9 × ( 5) × 6 × ( ...

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Byju's Answer

Standard VII

Mathematics

Properties of Multiplication of Integers

Encircle the ...

Question

Question 28

Encircle the odd one of the following:

(a) $(- 9) \times 5 \times 6 \times (- 3)$
(b) $9 \times (- 5) \times 6 \times (- 3)$
(c) $(- 9) \times (- 5) \times (- 6) \times 3$
(d) $9 \times (- 5) \times (- 6) \times 3$

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Solution

(a) $(- 9) \times 5 \times 6 \times (- 3) = (- 45) \times (- 18) = 810$
(b) $9 \times (- 5) \times 6 \times (- 3) = (- 45) \times (- 18) = 810$
(c) $(- 9) \times (- 5) \times (- 6) \times 3 = 45 \times (- 18) = - 810$
(d) $9 \times (- 5) \times 6 \times (- 3) = (- 45) \times (- 18) = 810$

So the odd one is option (c).

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Encircle the odd one of the following:

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Question 28 Encircle the odd one of the following: (a) (−9)×5×6×(−3) (b) 9×(−5)×6×(−3) (c) (−9)×(−5)×(−6)×3 (d) 9×(−5)×(−6)×3

(a) (−9)×5×6×(−3)=(−45)×(−18)=810 (b) 9×(−5)×6×(−3)=(−45)×(−18)=810 (c) (−9)×(−5)×(−6)×3=45×(−18)=−810 (d) 9×(−5)×6×(−3)=(−45)×(−18)=810 So the odd one is option (c).

Question 28

Encircle the odd one of the following:

(a) $(- 9) \times 5 \times 6 \times (- 3)$
(b) $9 \times (- 5) \times 6 \times (- 3)$
(c) $(- 9) \times (- 5) \times (- 6) \times 3$
(d) $9 \times (- 5) \times (- 6) \times 3$