End product in this reaction is CHCH - HBr - X KOH -A- CH 2- CHOHB- CH 2- CH 2 BrC- CH 3- CH 1 BrHD- CH 3- CH 2 Br

The correct option is A CH_2=CHOH CHCH + HBr → CH_2=CH_Br KOH→ CH_2=CH_2OH ...

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Addition of Halogen Acid for Alkynes

End product i...

Question

End product in this reaction is $C H C H + H B r \to X K O H \to$

$C H_{2} = C H O H$

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$C H_{3} - C H_{2} B r$

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$C H_{2} = C H_{2} B r$

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$C H_{3} - C H_{1} B r H$

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A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

{C H}_{2} = C H - {C H}_{3} + H B r \to {C H}_{3} C H (B r) - {C H}_{3}

{C H}_{3} {C H}_{2} {C H}_{2} B r {C H}_{3} O N a - ----- \to {C H}_{3} O H ?

{C H}_{3} {C H}_{2} {C H}_{2} B r {N H}_{3} - --- \to e x c e s s

{C H}_{3} {C H}_{2} {C H}_{2} {N H}_{2}

What will be the end product of this reaction ? $C H_{2} = C H_{2} + H . H_{2} S O_{4} \to$

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