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A Primer on Nucleophilies and Methods of Attack

End product o...

Question

End product of the following reaction is -
$C H_{3} C H_{2} C O O H$ $r e d P - -- \to C l_{2}$ $- ----- \to A l c . K O H$

C H_{2} = C H - O | | C - O H

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C H_{2} | O H C H_{2} C O O H

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C H_{2} = C H C O O H

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C H_{2} | C l C H | O H - C O O H

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Solution

The correct option is A
$C H_{2} = C H - O | | C - O H$

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Similar questions

C H_{2} - O H | C = C H | C l - O - M e | C H - C = C - C O O H

C H_{3} - O H | C H - C H_{2} - C H_{2} - O H C r O_{3} ⟶ P y r i d i n e c o l d P r o d u c t

p K_{b}

F - C H_{2} C H_{2} C O O H

C l - C H | C l - C H_{2} - C O O H

F - C H_{2} - C O O H

B r - C H_{2} - C H_{2} - C O O H

H - X

C H_{2} = C H - O H

C H_{2} = C H - C H_{2} O H

C H_{3} - C H_{2} - O H

C H_{3} - C H | O H - C H_{3}

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