You visited us 1 times! Enjoying our articles? Unlock Full Access!

Energy Levels

Energy above ...

Question

Energy above ground state
$n = 3$ ------------------------------ $6 e V$
$n = 2$ ------------------------------ $4 e V$
$n = 1$ ------------------------------ $0 e V$
In above shown figure, the energy levels of a hypothetical atom are shown. Calculate the energy of photon emitted when a electron is making transition from the third energy level to the second energy level.

10 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 2 eV
The energy of the emitted photon is equal to the difference in the two energy levels.
$\Rightarrow 6 e V - 4 e V = 2 e V$

Suggest Corrections

Similar questions

n = 4

E_{4} = 7 e V

n = 3

E_{3} = 6 e V

n = 2

E_{2} = 4 e V

n = 1

E_{1} = 0

4^{t h}

n = 3

n = 1

n = 4

E_{4} = 7 e V

n = 3

E_{3} = 6 e V

n = 2

E_{2} = 4 e V

n = 1

E_{1} = 0

E_{n} = - \frac{16}{n^{2}} e V

n = 1, 2, 3, . . . .

n = 3

Join BYJU'S Learning Program