Energy for 6.43 * 10 ^15 photos of 4.27 * 10^14 second -1 frequency in Einstein unit is

A)1.20 * 10^ -8

B) 2.58 * 10 ^ -3

C) 1.06 * 10^ -8

D) 8.33 * 10^ 7

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Solution

1mole =6.02210^23 photons
? mole=6.4310^15 photons

upon cross multiplying
6.4310^15photons1mole/6.02210^23 photons
=1.068 10^-8 mole.

An einstein is a unit defined as the energy in one mole (6.022×10²³) of photons.

1 einstein=1mole
? eistein = 1.06810^-8 moles

cross multiplying

1.06810^-8 einstein is the answer

option C is the answer

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Energy for 6.43 * 10 ^15 photos of 4.27 * 10^14 second -1 frequency in Einstein unit is A)1.20 * 10^ -8 B) 2.58 * 10 ^ -3 C) 1.06 * 10^ -8 D) 8.33 * 10^ 7

Energy for 6.43 * 10 ^15 photos of 4.27 * 10^14 second -1 frequency in Einstein unit is

A)1.20 * 10^ -8

B) 2.58 * 10 ^ -3

C) 1.06 * 10^ -8

D) 8.33 * 10^ 7