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Question

Energy involved to ionise O2(g) to O2(g) is 639 kJ mol1. If the ionisation enthalpy of O(g) is 141 kJ mol1. The second electron gain enthalpy of oxygen would be:

A
780 kJ mol1
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B
780 kJ mol1
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C
498 kJ mol1
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D
498 kJ mol1
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Solution

The correct option is B 780 kJ mol1
Given:
O(g)+2eO2(g) ; ΔH=639 kJ mol1 ...(i)
O(g)O(g)+e ; ΔH=141 kJ mol1 ...(ii)

Adding equation (i) and (ii), we get
O(g)+eO2(g) ; ΔH=780 kJ mol1 ...(iii)

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