Question

Energy levels A,B,C of an atom are shown below


If $E_A<E_B<E_C$, the wavelength emitted due to transistion from C to A is ${\lambda }_3$then correct statements of the following is

• A. ${\lambda }_3={\lambda }_1+{\lambda }_2$
• B. ${\lambda }_3=\frac{{\lambda }_1\times {\lambda }_2}{{\lambda }_2+{\lambda }_1}$
• C. ${\lambda }_1+{\lambda }_2+{\lambda }_3=0$
• D. ${\lambda }_3^2={\lambda }_1^2+{\lambda }_2^2$

Answer 1

The correct option is B ${\lambda }_3=\frac{{\lambda }_1\times {\lambda }_2}{{\lambda }_2+{\lambda }_1}$

$E_{CA}=E_{CB}+E_{BA}$
$\frac{hc}{{\lambda }_3}=\frac{hc}{{\lambda }_1}+\frac{hc}{{\lambda }_2}$
${\lambda }_3=\frac{{\lambda }_1\times {\lambda }_2}{{\lambda }_2+{\lambda }_1}$