Question

Energy needed in breaking a drop of radius R into n drops of radii r is given by

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Energy needed = Increment in surface energy

= (surface energy of n small drops) - (surface energy of one big drop)

$n4\pi r^{2}T-4\pi R^{2}T=4\pi T(n{r}^2-R^2)$