Question

Energy of an electron of H-atom in second Bohr’s orbit is

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$E_n=\frac{-2.172\times {10}^{-18}J}{n^2}=\frac{-2.172\times {10}^{-18}J}{2^2}=-5.44\times {10}^{-19}J$