Energy of electron in first orbit of hydrogen atom is:

- 13.6 e V

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- 27.2 e V

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- 54.4 e V

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none of the above

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Solution

The correct option is A $- 13.6 e V$
As for hydrogen atom,

$z = 1,$
$n = 1$ .

$E = - 13.6 \frac{z^{2}}{n^{2}} e V$ .

Substituting the value of $n, z$ we get

$E = - 13.6 e V$

Hence, the correct option is $A$

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13.6 e V

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The ionisation energy of hydrogen atom is 13.6 ev. What will be the ionisation energy of ${L i}^{+ 2}$ ions?

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