Question

Energy of photon is $E=hf$ and its momentum is $P=\frac{h}{\lambda }$, where $\lambda$ is the wavelength of photon with this assumption speed of light wabe is ______

• A. $\frac{P}{E}$
• B. $EP$
• C. $\frac{E}{P}$
• D. ${\left(\frac{E}{P}\right)}^2$

Answer 1

The correct option is C $\frac{E}{P}$

$E=hfP=\frac{h}{\lambda }c=\lambda f\therefore \frac{E}{P}=\frac{hf}{\frac{h}{\lambda }}=\lambda f\therefore c=\frac{E}{P}$