Energy required to move a body of mass m from an orbit of radius 2R to 3R is:

\frac{G M m}{12 R^{2}}

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\frac{G M m}{3 R^{2}}

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\frac{G M m}{8 R}

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\frac{G M m}{6 R}

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Solution

The correct option is D $\frac{G M m}{6 R}$
$Energy required = (Final potential-Initial potential)m$
$Energy required = - \frac{G M m}{3 R} - \frac{- G M m}{2 R} = \frac{G M m}{6 R}$

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Energy required to move a body of mass m from an orbit of radius 2R to 3R is:

The correct option is D GMm6REnergy required=(Final potential-Initial potential)mEnergy required=−GMm3R−−GMm2R=GMm6R

The correct option is D $\frac{G M m}{6 R}$
$Energy required = (Final potential-Initial potential)m$
$Energy required = - \frac{G M m}{3 R} - \frac{- G M m}{2 R} = \frac{G M m}{6 R}$