Energy shared in cylindrical region of length l extending from radius R1 to R2 and coaxial with long wire carrying current i is
A
μ0πi2l(R2−R1R1)
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B
μ0πi2lR2R1
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C
μ04πi2lln(R2R1)
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D
μ02πi2lln(R2R1)
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Solution
The correct option is Cμ04πi2lln(R2R1) Energy shared in small volume is dv dv=B22μ0×2πrdrl here B=μ02πir⇒dv=μ20i24π2r2.2πrdrl2μ0 v=∫dv=μ04πi2l∫R2R1drr=μ04πi2lln(R2R1)