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Question

Energy stored in between the plates of parallel plate capacitor of area A, separated by distance d is:

A
12ε0E2Ad
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B
12ε0E2Ad
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C
12ε0dE2A
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D
12Adε0E2
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Solution

The correct option is A 12ε0E2Ad
Energy stored in a capacitor of capacitance: E=12CV2
Capacitance of parallel plate capacitor =ϵ0Ad
Potential difference across parallel plate capacitor due to presence of electric field, V=E×d
Thus, energy stored in capacitor =12(ϵ0Ad)(Ed)2=12ϵ0E2Ad

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