Question

Engineering strain of a mild steel sample is recorded as 0.100% The true strain is

• A. 0.010%
• B. 0.055%
• C. 0.099%
• D. 0.101%

Answer 1

The correct option is C 0.099%

Given data

Engineering strain,

$ϵ=0.100$

True strain: $\overline{ϵ}=ln(1+ϵ)=ln(1+0.001)$

= 0.00099 = 0.099%