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Question
Enmesh bought x applies at 0.50 each and y kiwi fruit at 0.80 each. He sold the apples at 0.85 each and the kiwi fruit at 1.00 each. Which of the following algebraic expressions correctly shows the profit earned by Enmesh?
Enmesh bought x applies at 0.50 each and y kiwi fruit at 0.80 each. He sold the apples at 0.85 each and the kiwi fruit at 1.00 each. Which of the following algebraic expressions correctly shows the profit earned by Enmesh?
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Solution
The correct option is A 35x+20y
Enmesh bought x apples at 0.50 each, so cost price of apples=0.50xHe bought y kiwi fruit at 0.80 each, so cost price of kiwi fruit=0.80y
Total cost price of the fruits=0.5x+0.8yNow,Enmesh sold x apples at 0.85 each, so selling price of apples=0.85xHe sold y kiwi fruit at 1.00 each, so selling price of kiwi fruit=1.00y
Total selling price of the fruits=0.85x+yNow,Profit= total selling price-total cost price =0.85x+y−(0.5x+0.8y) =0.35x+0.20y in rupeesHere, only if we convert it to paisa, i.e; multiply by 100, profit becomes 35x+20y
Enmesh bought x apples at 0.50 each, so cost price of apples=0.50x
He bought y kiwi fruit at 0.80 each, so cost price of kiwi fruit=0.80y
Total cost price of the fruits=0.5x+0.8y
Now,
Enmesh sold x apples at 0.85 each, so selling price of apples=0.85x
He sold y kiwi fruit at 1.00 each, so selling price of kiwi fruit=1.00y
Total selling price of the fruits=0.85x+y
Now,
Profit= total selling price-total cost price
=0.85x+y−(0.5x+0.8y)
=0.35x+0.20y in rupees
Here, only if we convert it to paisa, i.e; multiply by 100, profit becomes 35x+20y
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