Enol form is more stable in

Cyclohexanone

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$C H_{3} C O C H_{2} C O O C_{2} H_{5}$

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$C H_{3} C O C H_{3}$

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$C H_{3} C H O$

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Solution

The correct option is B
$C H_{3} C O C H_{2} C O O C_{2} H_{5}$

The stabilizing effect of enolic form is the intramolecular hydrogen bond present in enols. This provides another source of increasing bonding and hence, increased stabilization. Thus, $C H_{3} C O C H_{2} C O O C_{2} H_{5}$ is more stable

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