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A bag contains $3$ red balls, $5$ black balls and $4$ white balls. A ball is drawn at random from the bag. The probability that the ball drawn is black is $\frac{5}{12}$ .

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Solution

Number of red balls $= 3$
Number of black balls $= 5$
Number of white balls $= 4$
Total number of balls $= 3 + 5 + 4 = 12$
P(getting a black ball) $= \frac{Number of black balls}{Total number of balls} = \frac{5}{12}$

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Enter 1 if it is true else enter 0.A bag contains 3 red balls, 5 black balls and 4 white balls. A ball is drawn at random from the bag. The probability that the ball drawn is black is 512.

Number of red balls =3Number of black balls =5Number of white balls =4Total number of balls =3+5+4=12P(getting a black ball) =Number of black ballsTotal number of balls=512

Enter 1 if it is true else enter 0.
A bag contains $3$ red balls, $5$ black balls and $4$ white balls. A ball is drawn at random from the bag. The probability that the ball drawn is black is $\frac{5}{12}$ .

Number of red balls $= 3$
Number of black balls $= 5$
Number of white balls $= 4$
Total number of balls $= 3 + 5 + 4 = 12$
P(getting a black ball) $= \frac{Number of black balls}{Total number of balls} = \frac{5}{12}$