Enthalpy of a reaction at 27- C is 15 kJ mol -1 The reaction will be feasible if entropy isA- greater than 50 J mol -1 K -1B- less than 50 Jmol -1 K -1C- 15 Jmol -1 K -1D- 50 Jmol -1 K -1

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Gibbs Free Energy & Spontaneity

Enthalpy of a...

Question

Enthalpy of a reaction at $27^{\circ} C$ is $15 k J m o l^{- 1}$ The reaction will be feasible if entropy is

15 J m o l^{- 1} K^{- 1}

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50 J m o l^{- 1} K^{- 1}

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greater than

50 J m o l^{- 1} K^{- 1}

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less than

50 J m o l^{- 1} K^{- 1}

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Solution

The correct option is C greater than $50 J m o l^{- 1} K^{- 1}$
We know,
$△ G = △ H - T △ S$
for a reaction to be feasible it should be sponteneous, that is when,
$△ G = - v e$
and for that $T △ S$ should be greater in magnitutde than $△ H$ i.e.
$\Rightarrow T △ S > △ H T = 27 + 273 = 300 K \Rightarrow 300 △ S > 15000 J m o l^{- 1} \Rightarrow △ S > 50 J m o l^{- 1} K^{- 1}$

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Gibbs Free Energy & Spontaneity

Standard XII Chemistry

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Enthalpy of a reaction at 27∘C is 15 kJ mol−1 The reaction will be feasible if entropy is

Enthalpy of a reaction at $27^{\circ} C$ is $15 k J m o l^{- 1}$ The reaction will be feasible if entropy is