Enthalpy of atomisation of a diamond is 600 kJ-mol - C diamond - C g-Find the bond energy of the C - C bond- Give your answer in kJ-mol-

#160;in producing 1 mole C(g), 1/2× #160; 4 = 2 C C bonds arebroken. #160; 2 ϵ_c c = 600 ϵ_c c = 300 kJ/mol ...

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Standard XII

Chemistry

sp2 Hybridisation

Enthalpy of a...

Question

Enthalpy of atomisation of a diamond is $600 k J / m o l$ .
$C (d i a m o n d) \to C (g) .$
Find the bond energy of the $C - C$ bond.
Give your answer in $k J / m o l$ .

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Solution

in producing 1 mole C(g),
$\frac{1}{2} \times 4 = 2$ C-C bonds are
broken.
$2 ϵ_{c - c} = 600$
$ϵ_{c - c} = 300 k J / m o l$

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Enthalpy of atomisation of a diamond is 600kJ/mol .C(diamond)→C(g).Find the bond energy of the C−C bond. Give your answer in kJ/mol.

in producing 1 mole C(g),12×4=2 C-C bonds arebroken.2ϵc−c=600ϵc−c=300kJ/mol

Enthalpy of atomisation of a diamond is $600 k J / m o l$ .
$C (d i a m o n d) \to C (g) .$
Find the bond energy of the $C - C$ bond.
Give your answer in $k J / m o l$ .

in producing 1 mole C(g),
$\frac{1}{2} \times 4 = 2$ C-C bonds are
broken.
$2 ϵ_{c - c} = 600$
$ϵ_{c - c} = 300 k J / m o l$