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Standard XII

Chemistry

Lattice Energy

Enthalpy of c...

Question

Enthalpy of combustion of carbon to ${C O}_{2}$ is -393.5kJ per mol. Calculate the heat released upon formation of 35.2g of ${C O}_{2}$ from carbon and dioxygen gas

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Solution

Given,
$C_{(s)} + O_{2 (g)} \to C O_{2 (g)}$
$△ H_{f} = - 393.5 k J / m o l$
$∴$ Heat released on formation of $H H g$ or 1 mole of $C O_{2} = 393.5 k J / m o l$
$∴$ Heat released on formation of $35.2 g m$ of $C O_{2} = \frac{- 393.5}{44} \times 35.2 = - 315 k J m o l^{- 1}$

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Enthalpy of combustion of carbon to CO2 is -393.5kJ per mol. Calculate the heat released upon formation of 35.2g of CO2 from carbon and dioxygen gas

Given,C(s)+O2(g)→CO2(g)△Hf=−393.5kJ/mol∴ Heat released on formation of HHg or 1 mole of CO2=393.5kJ/mol∴ Heat released on formation of 35.2gm of CO2=−393.544×35.2=−315kJmol−1

Enthalpy of combustion of carbon to ${C O}_{2}$ is -393.5kJ per mol. Calculate the heat released upon formation of 35.2g of ${C O}_{2}$ from carbon and dioxygen gas

Given,
$C_{(s)} + O_{2 (g)} \to C O_{2 (g)}$
$△ H_{f} = - 393.5 k J / m o l$
$∴$ Heat released on formation of $H H g$ or 1 mole of $C O_{2} = 393.5 k J / m o l$
$∴$ Heat released on formation of $35.2 g m$ of $C O_{2} = \frac{- 393.5}{44} \times 35.2 = - 315 k J m o l^{- 1}$