Enthalpy of hydrogenation is the enthalpy change when one mole of unsaturated compound is converted to saturated compound. Heat of hydrogenation helps to calculate resonance energy.
The heats of neutralization of $C H_{3} C O O H, H C O O H, H C N$ and $H_{2} S$ are –12.8, –13.2, –3.2 and –3.9 kcal per equivalent. Arrange these acids in increasing order of strength.

H 2_{S} < H C N < H C O O H < C H_{3} C O O H

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H C N < H_{2} S < C H_{3} C O O H < H C O O H

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H C O O H < C H_{3} C O O H < H_{2} S < H C N

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C H_{3} C O O H < H C O O H < H C N < H_{2} S

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Solution

The correct option is B $H C N < H_{2} S < C H_{3} C O O H < H C O O H$
The greater the magnitude of heat of neutralization the more is the strength of the acid. So increasing order of strength is $H C N < H_{2} S < C H_{3} C O O H < H C O O H$

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Similar questions

The heats of neutralisation of $C H_{3} C O O H$ , HCOOH, HCN and $H_{2} S$ are -12.8, -13.2, -3.2 and -3.9 kcal per equivalent. Arrange these acids in increasing order of strength.

Q. The pH of 1N aqueous solutions of

H C l, C H_{3} C O O H a n d H C O O H

follows the order

Q. Enthalpy of hydrogenation is the enthalpy change when one mole of unsaturated compound is converted to saturated compound. Heat of hydrogenation helps to calculate resonance energy.
The standard enthalpy of combustion at

25^{\circ} C

of hydrogen, cyclohexene

(C_{6} H_{10})

and cyclohexane

(C_{6} H_{12})

are –300,–3600 and –3770 KJ/mole respectively. Calculate the heat of hydrogenation of cyclohexene.

Q. The correct descending order of the heat liberated (in

k J

) during the neutralisation of the acids

C H_{3} C O O H (W), H F (X), H C O O H (Y)

and

H C N (Z)

under identical conditions is:

(

K_{a}

C H_{3} C O O H = 1.8 \times 10^{- 5}, H C O O H = 1.8 \times 10^{- 4}, H C N = 4.9 \times 10^{- 10}

and

H F = 3.2 \times 10^{- 4}

)

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The correct option is B HCN<H2S<CH3COOH<HCOOHThe greater the magnitude of heat of neutralization the more is the strength of the acid. So increasing order of strength is HCN<H2S<CH3COOH<HCOOH

The correct option is B $H C N < H_{2} S < C H_{3} C O O H < H C O O H$
The greater the magnitude of heat of neutralization the more is the strength of the acid. So increasing order of strength is $H C N < H_{2} S < C H_{3} C O O H < H C O O H$