Enthalpy of hydrogenation is the enthalpy change when one mole of unsaturated compound is converted to saturated compound. $Δ_{H} h y d r o g e n a t i o n$ helps to calculate resonance energy.

The heat of neutralization of $C H_{3} C O O H, H C O O H, H C N$ and $H_{2} S$ are -12.8, -13.2, -3.2 and -3.9 Kcal per equivalent. Arrange these acids in increasing order of strength.

$H_{2} S < H C N < H C O O H < C H_{3} C O O H$

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$H C N < H_{2} S < C H_{3} C O O H < H C O O H$

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$H C O O H < C H_{3} C O O H < H_{2} S < H C N$

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$C H_{3} C O O H < H C O O H < H C N < H_{2} S$

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Solution

The correct option is B
$H C N < H_{2} S < C H_{3} C O O H < H C O O H$

Acidic strength $\propto$ heat of neutralisation.

The heat of neutralisation of any strong acid will be that of formation of water. As the acid gets weaker, fewer ions are furnished by it, reducing the heat of neutralisation when it reacts with a base.

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The heats of neutralisation of $C H_{3} C O O H$ , HCOOH, HCN and $H_{2} S$ are -12.8, -13.2, -3.2 and -3.9 kcal per equivalent. Arrange these acids in increasing order of strength.

Q. The pH of 1N aqueous solutions of

H C l, C H_{3} C O O H a n d H C O O H

follows the order

Enthalpy of hydrogenation is the enthalpy change when one mole of unsaturated compound is converted to saturated compound. $Δ_{H} h y d r o g e n a t i o n$ helps to calculate resonance energy.

The standard enthalpy of combustion at $25^{\circ} C$ of hydrogen, cyclohexene and cyclohexane are -300, -3600 and -3770 KJ/mole respectively. Calculate the heat of hydrogenation of cyclohexene.

Q. Given : Enthalpy of ionization of two acids:

Δ H^{\circ} (H C N) = 45.2 k J m o l^{- 1}

Δ H^{\circ} (C H_{3} C O O H) = 2.1 k J m o l^{- 1}

Which relationship for the two acids is true?

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The correct option is B HCN<H2S<CH3COOH<HCOOH Acidic strength ∝ heat of neutralisation. The heat of neutralisation of any strong acid will be that of formation of water. As the acid gets weaker, fewer ions are furnished by it, reducing the heat of neutralisation when it reacts with a base.