Question

Enthalpy of neutralization for strong acid and strong base forming 3 mole of water is:

• A. $-57.6kJ$
• B. $\frac{-57.6}{3}kJ$
• C. $-57.6\times 3kJ$
• D. $-57.6\times 6kJ$

Answer 1

Answer: (C)

$-57.6\times 3kJ$

It is a special case of the enthalpy of reaction. It is defined as the energy released with the formation of 1 mole of water. The standard enthalpy change of neutralization for a strong acid and base is $-57.62kJ/mol$.

Here, 3 moles of water is formed therefore enthalpy of neutralization will be ($-57.62\times 3kJ$).