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Question

Enthalpy of neutralization for strong acid and strong base forming 3 mole of water is:

A
57.6 kJ
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B
57.63 kJ
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C
57.6×3 kJ
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D
57.6×6 kJ
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Solution

The correct option is D 57.6×3 kJ
It is a special case of the enthalpy of reaction. It is defined as the energy released with the formation of 1 mole of water. The standard enthalpy change of neutralization for a strong acid and base is 57.62kJ/mol.
Here, 3 moles of water is formed therefore enthalpy of neutralization will be (57.62×3 kJ).

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