Question

Enthalpy of neutralization of 10 mL of each 1 M $HCl$ and 1M $H_{2}S{O}_4$ are neutralized by 1 M $NaOH$ solution that liberate the heat of $a$ and $b$ kJ/mol respectively. What is relation between $a$ and $b$?

Answer 1

As $H_{2}S{O}_4$ has two removable hydrogen it produces high enthalpy of neutralisation for 1 mole of $H_{2}S{O}_4$ compared to $HCl$ which has one removable hydrogen.

$HCl+NaOH⟶NaCl+H_{2}O\Delta H=a$

$H_{2}S{O}_4+2NaOH⟶N{a}_{2}S{O}_4+2H_{2}O\Delta H=b$

Here, $b=2a$.