Entropy change - ds - heat added or released - temperature We ds - dQ - T- If we plot entropy-temperature graph S - T - then which of the curve resembles with carnot cycle-

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Standard XII

Physics

y-x-t Graph

Entropy chang...

Question

Entropy change $= d s = \frac{h e a t a d d e d o r r e l e a s e d}{t e m p e r a t u r e}$
We can say $d s = \frac{d Q}{T} .$ If we plot entropy-temperature graph (S - T), then which of the curve resembles with carnot cycle?

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Solution

The correct option is A
For Carnot cycle, two steps are isothermal and for two steps $Q = 0$ , hence $d s = 0$ .

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Entropy change =ds=heat added or releasedtemperature We can say ds=dQT. If we plot entropy-temperature graph (S - T), then which of the curve resembles with carnot cycle?

The correct option is A For Carnot cycle, two steps are isothermal and for two steps Q=0, hence ds=0.

Entropy change $= d s = \frac{h e a t a d d e d o r r e l e a s e d}{t e m p e r a t u r e}$
We can say $d s = \frac{d Q}{T} .$ If we plot entropy-temperature graph (S - T), then which of the curve resembles with carnot cycle?

The correct option is A
For Carnot cycle, two steps are isothermal and for two steps $Q = 0$ , hence $d s = 0$ .