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Byju's Answer
Standard XII
Chemistry
Gibb's Energy and Nernst Equation
Entropy chang...
Question
Entropy change in JK
−
1
is___________.
(Give answer to the nearest integer)
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Solution
At 298 K,
E
=
0.0455
V
At 308 K,
E
=
0.0455
+
3.38
×
10
−
4
×
10
=
0.04888
V
Δ
G
=
−
n
F
E
At 298 K,
Δ
G
=
2
×
96500
×
0.0455
=
−
8781.5
J
/
m
o
l
At 308 K,
Δ
G
=
2
×
96500
×
0.04888
=
−
9433.84
J
/
m
o
l
Δ
H
=
Δ
H
−
T
Δ
S
−
8781.5
=
Δ
H
−
298
Δ
S
.......(1)
−
9433.84
=
Δ
H
−
308
Δ
S
......(2)
Subtract equation (2) from equation (1)
652.34
=
10
Δ
S
Δ
S
=
65.234
So, the correct answer is
65
.
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