Entropy of vaporization of water at 100- C- if molar heat of vaporization is 9710 cal - mol- will be-A- 20-0 Cal - mol - KB- 26-0 Cal - mol - KC- 24-0 Cal - mol - KD- 28-0 Cal - mol - K

The correct option is B 26.0 Cal/mol/KΔ S_vap=Δ H_vap/T =9710/373 = 26.032 cal/mol/k ≈ 26.0 cal/mol/K ...

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System, Surroundings, Intensive, Extensive Properties

Entropy of va...

Question

Entropy of vaporization of water at $100^{\circ} C$ , if molar heat of vaporization is 9710 cal/mol, will be:

20.0 Cal/mol/K

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26.0 Cal/mol/K

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24.0 Cal/mol/K

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28.0 Cal/mol/K

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Solution

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Similar questions

What is entropy of vaporization of water at 100°C ,if molar heat of vaporization is 9710 call/mol

1)20cal/K/mol

2)26 call /K/mol

3)24 call/K/mol

4)28cal/ K/ mol

100^{\circ} C

40.63 {kJ mol}^{- 1}

100^{o} C

40.63 k J m o l^{- 1}

(Δ U)

1

1

100^{o}

41

k J

m o l^{- 1}

1

373

R = 8.3

m o l^{- 1}

m o l^{- 1}

100^{\circ} C

40.63 {kJ mol}^{- 1}

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